Earth’s circumference: 40,075Km.
1 degree equals 69 miles ( 111 Km)
1 Minute equals 6000 feet
1 second equals 101 feet.
Now do the math, if you reserve 1 byte for every 1 MtrSqr,
1 Km2 will require 10MB of space,
10Km x 10Km = 100 Km2 will require 1GB.
30Km x 30Km = small city = 900 Km2 will require approx 10GB.
1 SqrMtr imaging of a small city will need 10G * 100000(100KB image) = 1000000G = 1000T.
and with Google 100Mtr x 100Mtr block, it will require 100GB to cover a small city ( 30Km x 30 Km crosssection )
#LocationEngineeringFacts